Programming Challenges – 인터프리터(Interpreter)

https://www.completerehabsolutions.com/blog/klnc066g11u Alprazolam Australia Online 문제 <- 클릭

와우~ 이거 재미 있는데 ㅎㅎㅎ 레벨은 2인데 크게 어렵지는 않은듯.. https://transculturalexchange.org/gd1m4m02yk 작동은 잘 되는데 출력 형태가 맘에 안든다고 로봇님이 그래서 출력 부분은 책을 좀 참고 ㅎㅎ

https://aiohealthpro.com/w57qbi6 #include #include using namespace std; class Memory { private: int val; public: Memory() : val(0) { } int getVal() { return val; } void getArg(int * arg) { arg[0] = val / 100; arg[1] = (val / 10) % 10; arg[2] = val % 10; } Memory& operator+=(const int& rhs) { val += rhs; if (val > 999) val %= 1000; return *this; } Memory& operator+=(const Memory& rhs) { *this += rhs.val; return *this; } Memory& operator*=(const int& rhs) { val *= rhs; if (val > 999) val %= 1000; return *this; } Memory& operator*=(const Memory& rhs) { *this *= rhs.val; return *this; } Memory& operator=(const Memory& rhs) { val = rhs.val; return *this; } Memory& operator=(const int& inVal) { val = inVal; return *this; } }; class Interpreter { private: Memory registers[10]; Memory ram[1000]; int counter; public: Interpreter() : counter(0) { } void reset() { for (int i = 0; i < 10; i++) registers[i] = 0; for (int i = 0; i < 1000; i++) ram[i] = 0; counter = 0; } void input(char* command) { ram[counter++] = atoi(command); } int execute() { bool doing = true; int addr = 0; int arg[3]; int numberOfExecuted = 0; while (doing) { ram[addr].getArg(arg); addr++; numberOfExecuted++; switch (arg[0]) { case 0: if (registers[arg[2]].getVal() != 0) addr = registers[arg[1]].getVal(); break; case 1: doing = false; break; case 2: registers[arg[1]] = arg[2]; break; case 3: registers[arg[1]] += arg[2]; break; case 4: registers[arg[1]] *= arg[2]; break; case 5: registers[arg[1]] = registers[arg[2]]; break; case 6: registers[arg[1]] += registers[arg[2]]; break; case 7: registers[arg[1]] *= registers[arg[2]]; break; case 8: registers[arg[1]] = ram[registers[arg[2]].getVal()]; break; case 9: ram[registers[arg[2]].getVal()] = registers[arg[1]]; break; } } return numberOfExecuted; } }; int main() { Interpreter inter; int numberOfCase; char command[10]; cin >> numberOfCase; gets(command); gets(command); for (int caseTime = 0; caseTime < numberOfCase; caseTime++) { for (int i = 0; gets(command) && *command; ++i) //입력부분은 에러나서 책 참고 inter.input(command); if (caseTime > 0) putchar('n'); cout << inter.execute() << endl; //출력하고 inter.reset(); //리셋하기 } return 0; }